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（6分）某同学在查阅资料时得知：市售纯碱样品常混有氯化钠杂质。 该同学设计了如下图中的装置进行实验，测定市售纯碱样品中碳酸钠的质量分数。（水蒸气的影响忽略不计，夹持装置已略去） 主要实验步骤如下： ①按图组装仪器，并检查装置的气密性； ②称量5.5 g市售纯碱样品放入烧瓶中，加适量蒸馏水溶解，得到试样溶液； ③从分液漏斗滴入稀硫酸，直到不再产生气体时为止； ④缓缓鼓入一定量的N 2 ； ⑤称量B瓶及溶液的质量，发现增重2.2 g。 请回答下列问题： （1）写出A中发生反应的化学方程式 。 （2）鼓入一定量的N 2 的目的是 。装置C中澄清石灰水的作用是 。 （3）如果将分液漏斗中的稀硫酸换成浓盐酸，测试的结果（填偏高、偏低或不变） 。 （4）该样品中碳酸钠的质量分数为 %（结果保留到小数点后一位）。 （5）若用与上述实验反应原理不同的实验来测定纯碱样品中碳酸钠的质量分数，请用化学方程式表示实验原理 。
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A.
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A.
Providing fuel.
B.
Offering shade.
C.
Preventing natural disaster.
D.
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