皮皮学,免费搜题
登录
logo - 刷刷题
搜题
【多选题】
下列选项中哪些属于《海牙规则》的规定?( )
A.
承运人对于因船长、船员、引水员或承运人的雇用人在驾驶或管理船舶中的行为、疏忽或不履行职责可以免责
B.
承运人对货物的灭失或损害责任以每件或每单位10,000金法郎或每公斤30金法郎为限,两者以
C.
承运人应当适当和谨慎地装载、操作、积载、运送、保管、照料和卸载所承运的货物
D.
诉讼效为l年
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
微信内点击右上角“…”即可分享
反馈
参考答案:
举一反三
【简答题】Complete the following sentences by choosing the best word. respectful named race respect bound naming debt respective But a man _______ Al Herpin turned out to be a real exception, for he...
【简答题】编写递归算法,将二叉树中所有结点的左、右子树相互交换。Status ExchangeBiTree(BiTree& T){ BiTree p; if(T){ p=T->lchild; T->lchild=T->rchild; T->rchild=p; ; ExchangeBiTree(T->rchild); } return OK;}
【单选题】Flinders' discoveryAboard Investigator, Flinders reached and named Cape Leeuwin on 6 December 1801, and proceeded to make a survey along the southern coast of the Australian mainland. On his way he st...
A.
Flinders reached and named Cape Leeuwin on 6 December 1801.
B.
Flinders proceeded to Sydney, arriving on 9 May 1802.
C.
Flinders jettisoned two wrought-iron anchors which were found by drivers.
D.
The best bower anchor is on display at the South Australian Maritime Museum.
【简答题】试述分组选配法的特点。
【单选题】编写递归算法,将二叉树中所有结点的左、右子树相互交换。 StatusExchangeBiTree(BiTree& T) { BiTree p; if(T){ p=T->lchild; T->lchild=T->rchild; T->rchild=p; ExchangeBiTree(T->lchild); } return OK; }
A.
ExchangeBiTree(p);
B.
ExchangeBiTree(T->rchild);
C.
ExchangeBiTree(T->lchild->rchild);
D.
ExchangeBiTree(T);
【单选题】Flinders' discoveryAboard Investigator, Flinders reached and named Cape Leeuwin on 6 December 1801, and proceeded to make a survey along the southern coast of the Australian mainland. On his way he st...
A.
1799.
B.
1800.
C.
1801.
D.
1802.
【简答题】同步器有几种?为什么变速器中要装有同步器?
【简答题】有关哀悯、吊唁、忧患的典礼称为凶礼,大多是在发生不幸事件之后,( )和( )的礼仪。主要包括丧礼和荒礼两大类。
【简答题】He was named captain of the team.
【单选题】写递归算法,将二叉树中所有结点的左、右子树相互交换。 Status ExchangeBiTree(BiTree& T) { BiTreep; if(T){ p=T->lchild; T->lchild=T->rchild; T->rchild=p; ExchangeBiTree(T->lchild); __________ } returnOK; }
A.
A.ExchangeBiTree(p);
B.
ExchangeBiTree(T->rchild);
C.
ExchangeBiTree(T->lchild->rchild)
D.
ExchangeBiTree(T);
相关题目:
参考解析:
知识点:
题目纠错 0
发布
创建自己的小题库 - 刷刷题