现有如下解析JSON格式数据的程序片断,请并根据注释在空白划线处填写代码。 String jsonData = [ {"id":"5","version":"5.5","name":"Angry Birds"}, {"id":"6","version":"7.0","name":"Clash of Clans"}, {"id":"7","version":"3.5","name":"Hey Day"} ]; private void parseJSONWithJSONObject(String jsonData) { try { // 将JSON格式字符串转换成JSON数组 JSONArray jsonArray = (1)_____________________; for (int i = 0; i < jsonArray.length(); i++) { // 根据循环变量i取得JSON数组中JSON对象 JSONObject jsonObject = (2)_____________________; int id =(3)_____________________;// 取得id的值 String name =(4)_____________________;// 取得name的值 Double version =(5)_____________________;// 取得version的值 } } catch (Exception e) { e.printStackTrace(); } }