已知函数f(x)= x 3 - x 2 +x+b,其中a,b∈R. (1)若曲线y=f(x)在点P(2,f(2))处的切线方程为y=5x-4,求函数f(x)的解析式. (2)当a>0时,讨论函数f(x)的单调性.
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