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【判断题】
收益性物业的运营费用是除抵押贷款还本付息外物业发生的所有费用。
A.
正确
B.
错误
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参考答案:
举一反三
【单选题】Ms. Sykes is an ______ manager who is always able to get the best out of her employees.
A.
imaginary
B.
exclusive
C.
inactive
D.
effective
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【简答题】运行下面的汇编语言程序,在NUM内存单元中得到的结果是______。 DSEG SEGMENT DAT DB 5,13,4,-2,-6,23,3,1,9,0 CNT EQU S-DAT-1 NUM DB ? DSEG ENDS SSEG SEGMENT STACK DB 256 DUP(0) SSEG ENDS CSEG SEGMENT ASSUME DS:DSEG,SS:SSEG,CS:CSEG...
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【简答题】need to be put forward and where it is too vital to get the best out of the situation ____
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【简答题】结构或构件保持原有 的能力称为稳定性。
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【单选题】下面程序运行后的结果是:( ) #include void inc(void) { static int a=10; a++; printf(“a=%d ”,a); } void main() { int i; for(i=0;i<3;i++) inc(); }
A.
a=11 a=11 a=11
B.
a=11 a=11 a=11
C.
a=10 a=11 a=12
D.
a=10 a=10 a=10
E.
a=11 a=12 a=13
F.
a=11 a=11 a=11
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【单选题】下面程序的运行结果是 #include #inc1ude main() { char a[80」="AB",b[80]="LMNP"; int i=0; strcat(a,b); whi1e(a[i++]!='\0') b[i]=a[i]; puts(b); }
A.
LB
B.
ABLMNP
C.
AB
D.
LBLMNP
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【单选题】To get the best out of your business card in an international business meeting.
A.
Make sure it is printed on heavy card stock in a fancy font
B.
Whip it out of an expensive gold business-card case engraved with your name.
C.
Have it translated into the native tongue, and present it with their language face-up.
D.
Don't be shy about giving them out to everyone you meet.
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【单选题】下面程序运行后的结果是:( ) #include void inc(void) { static int a=10; a++; printf(“a=%d ”,a); } void main() { int i; for(i=0;i<3;i++) inc(); }
A.
a=11 a=11 a=11
B.
a=10 a=11 a=12
C.
a=10 a=10 a=10
D.
a=11 a=12 a=13
查看完整题目与答案
【简答题】下面程序的运行结果是______。 main() { void inc1();void inc2(); inc1();inc1();inc1(); inc2();inc2();inc2();} void inc1() { int x=0; x++; printf("in inc1 x=%d\n",x);} void inc2() { static int x=0; x++; printf("...
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【简答题】构件保持()的能力称为稳定性。
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相关题目:
【单选题】Ms. Sykes is an ______ manager who is always able to get the best out of her employees.
A.
imaginary
B.
exclusive
C.
inactive
D.
effective
查看完整题目与答案
【简答题】运行下面的汇编语言程序,在NUM内存单元中得到的结果是______。 DSEG SEGMENT DAT DB 5,13,4,-2,-6,23,3,1,9,0 CNT EQU S-DAT-1 NUM DB ? DSEG ENDS SSEG SEGMENT STACK DB 256 DUP(0) SSEG ENDS CSEG SEGMENT ASSUME DS:DSEG,SS:SSEG,CS:CSEG...
查看完整题目与答案
【简答题】need to be put forward and where it is too vital to get the best out of the situation ____
查看完整题目与答案
【简答题】结构或构件保持原有 的能力称为稳定性。
查看完整题目与答案
【单选题】下面程序运行后的结果是:( ) #include void inc(void) { static int a=10; a++; printf(“a=%d ”,a); } void main() { int i; for(i=0;i<3;i++) inc(); }
A.
a=11 a=11 a=11
B.
a=11 a=11 a=11
C.
a=10 a=11 a=12
D.
a=10 a=10 a=10
E.
a=11 a=12 a=13
F.
a=11 a=11 a=11
查看完整题目与答案
【单选题】下面程序的运行结果是 #include #inc1ude main() { char a[80」="AB",b[80]="LMNP"; int i=0; strcat(a,b); whi1e(a[i++]!='\0') b[i]=a[i]; puts(b); }
A.
LB
B.
ABLMNP
C.
AB
D.
LBLMNP
查看完整题目与答案
【单选题】To get the best out of your business card in an international business meeting.
A.
Make sure it is printed on heavy card stock in a fancy font
B.
Whip it out of an expensive gold business-card case engraved with your name.
C.
Have it translated into the native tongue, and present it with their language face-up.
D.
Don't be shy about giving them out to everyone you meet.
查看完整题目与答案
【单选题】下面程序运行后的结果是:( ) #include void inc(void) { static int a=10; a++; printf(“a=%d ”,a); } void main() { int i; for(i=0;i<3;i++) inc(); }
A.
a=11 a=11 a=11
B.
a=10 a=11 a=12
C.
a=10 a=10 a=10
D.
a=11 a=12 a=13
查看完整题目与答案
【简答题】下面程序的运行结果是______。 main() { void inc1();void inc2(); inc1();inc1();inc1(); inc2();inc2();inc2();} void inc1() { int x=0; x++; printf("in inc1 x=%d\n",x);} void inc2() { static int x=0; x++; printf("...
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【简答题】构件保持()的能力称为稳定性。
查看完整题目与答案
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