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阅读理 若p、q、m为整数，且三次方程x 3 +px 2 +qx+m=0有整数解c，则将c代入方程得：c 3 +pc 2 +qc+m=0，移项得：m=-c 3 -pc 2 -qc，即有：m=c×（-c 2 -pc-q），由于-c 2 -pc-q与c及m都是整数，所以c是m的因数．上述过程说明：整数系数方程x 3 +px 2 +qx+m=0的整数解只可能是m的因数．例如：方程x 3 +4x 2 +3x-2=0中-2的因数为±1和±2，将它们分别代入方程x 3 +4x 2 +3x-2=0进行验证得：x=-2是该方程的整数解，-1，1，2不是方程的整数解． 解决问题： （1）根据上面的学习，请你确定方程x 3 +x 2 +5x+7=0的整数解只可能是哪几个整数？ （2）方程x 3 -2x 2 -4x+3=0是否有整数解？若有，请求出其整数解；若没有，请说明理由．
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