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【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。此时给予该患者的首要处理措施是
A.
固定胸腔
B.
吸氧
C.
应用抗生素
D.
半卧位
E.
补充血容重
【简答题】Generally, the pH value of normal rain is 5-6. However, the pH value of acid rain is .
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和吸气时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼气时无明显变化
E.
吸气时内陷,呼气时外突
【单选题】The pancreatic glucokinase of a patient with MODY had a mutation replacing a leucine with a proline. The result was that the Km for glucose was decreased from a normal value of 6 mM to a value of 2.2 ...
A.
The patient ’ s enzyme requires a lower concentration of glucose to reach ½ Vmax.
B.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose <2.2 mM.
C.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose >2.2 mM.
D.
At near-saturating glucose concentration, the patient would need 90 to 100 times more enzyme than normal to achieve normal rates of glucose phosphorylation.
E.
As blood glucose levels increase after a meal from a fasting value of 5 to 10 mM, the rate of the patient ’ s enzyme will increase more than the rate of the normal enzyme.
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和呼吸时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼吸时无明显变化
E.
吸气时内陷,呼气时外突
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动极度呼吸困难。此时给予该患者的首要处理措施是
A.
固定胸腔
B.
吸氧
C.
应用抗生素
D.
半卧位
E.
补充血容量
【简答题】Translate : Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modifify the nature of control. Negative ...
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。该患者的病理生理改变不包括
A.
纵膈扑动
B.
胸膜腔负压消失
C.
回心血量下降
D.
进行性呼吸困难
E.
缺氧、二氧化碳潴留
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。该患者的病理生理改变不包括
A.
纵隔扑动
B.
胸膜腔负压消失
C.
回心血量下降
D.
进行性呼吸困难
E.
缺氧、二氧化碳潴留
【简答题】Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modify the nature of control. Negative feedback syste...
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