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【简答题】
A.The man shouldn't hesitate to take the course. B.The man should talk with the professor first. C.The course isn't open to undergraduates. D.The course will require a lot of reading.
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【单选题】- What do you think about the service of the coffee shops in this town? - I think the service in most of the shops is ___ and the waiters are friendly.
A.
electric
B.
scale
C.
efficient
D.
select
【单选题】现有两个非常大的某昆虫种群,个体间随机交配,没有迁入和迁出,无突变,自然选择对A和a基因控制的形状没有作用。种群1的A基因频率为80%,a基因频率为20%;种群2的A基因频率为60%,a基因频率为40%。假设这两个种群大小相等,地理隔离不再存在,两个种群完全合并为一个可随机交配的种群,则下一代中Aa的基因型频率是()
A.
75%
B.
50%
C.
42%
D.
21%
【单选题】《我的母亲》的作者是( )
A.
朱自清
B.
郁达夫
C.
鲁迅
D.
老舍
【单选题】现有两个非常大的某昆虫种群,个体间随机交配,没有迁 入 和迁出,无突变,自然选择对A和a基因控制的性状没有作用。种群1的A基因频率为80%,a基因频率为20%;种群2的A基因频率为60%,a基因频率为40%。假设这两个种群大小相等,地理隔离不再存在,两个种群完全合并为一个可随机交配的种群,则下一代中Aa的基因型频率是
A.
75%
B.
50%
C.
42%
D.
21%
【单选题】In Amsterdam, the capital of Holland, there is a unique Children Restaurant. It is run wholly by the children. From the manager to the cooks, cashiers, waiters or waitresses and other staff members ar...
A.
can earn only four dollars a day
B.
are fond of working there
C.
will have to work there for over a month
D.
do not need to be trained before they work in the restaurant
【单选题】The waiters in this restaurant will ( ) to serve you sincerely.
A.
do their little
B.
try their little
C.
do their utmost
D.
take their best
【简答题】Listen to this conversation in a restaurant in Beijing. How many kinds of Dim Sum do the waiters have on their trollies?
【单选题】现有两个非常大的某昆虫种群,个体间随机交配,没有迁入和迁出,无突变,自然选择对A和a基因控制的性状没有作用.种群1的A基因频率为80%,a基因频率为20%;种群2的A基因频率为60%,a基因频率为40%.假设这两个种群大小相等,地理隔离不再存在,两个种群完全合并为一个可随机交配的种群,则下一代中Aa的基因型频率是()
A.
75%
B.
50%
C.
42%
D.
27%
【简答题】In Amsterdam, the capital of Holland, there is a unique Children Restaurant. It is run wholly by the children. From the manager to the cooks, cashiers, waiters or waitresses and other staff members ar...
【单选题】Cortex-M3 支持位带操作,可以使用加载 / 存储指令来对单一的比特进行读写。对应 SRAM 中的某一个比特对应的未带别名区的地址为: AliasAddr = 0x22000000 + ( ( A - 0x20000000 ) * 8 + n ) * 4 = 0x22000000 + ( A-0x20000000 )* 32 + n * 4. 在对 0x20000000 第二位使用位带进行读...
A.
0x20000008
B.
0x22000008
C.
0x2000000C
D.
0x2200000C
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