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【单选题】
公司型基金依据()设立并营运。
A.
发起人协议
B.
基金公司章程
C.
基金招募说明书
D.
基金合同
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举一反三
【简答题】小红和小丽对问题“若方程组 a 1 x+ b 1 y= c 1 a 2 x+ b 2 y= c 2 的解是 x=3 y=-4 ,求方程组 3 a 1 x+2 b 1 y=5 c 1 3 a 2 x+2 b x y=5 c 2 的解”提出各自的想法.小红说:“这个题目好象条件不够,不能求解”;小丽说:“能不能把第二个方程组的两个方程的两边都除以5,通过整体代换的方法来解决”.参考他们的讨论,你认为这...
【简答题】I have a friend who lives by a three-word philosophy: Seize the moment. Just possibly, she may be the wisest woman on this planet. Too many people put off something that brings them joy just because t...
【单选题】进行英语写作课的时候,教师可以随时把某一范文或是某一学生的作文转播到所有学生的终端,进行讲评,让学生有直观、具体的认识,这中形式能够______。
A.
为教师的演示教学提供新的方式
B.
扩大和紧密英语学习的共同体
C.
促进学生主动构建的英语学习
D.
创设英语学习环境
【简答题】I have a friend who had financial problems and needed my help occasionally. He was in his final year in University while I was in my third year. He needed some money for school fees and other academic...
【简答题】I have a friend who had a stammer (口吃) in his childhood, but he dreamed of becoming a missionary(传教士). When he told his own desire to his friends and relatives, some of whom laughed at him, and some e...
【单选题】下述程序的输出结果是( )。 #include <stdio.h> int f(n) int n { if(n==0 | | n==1) return 3 return n-f(n-2) } void main() {printf('/n%d',f(10)) }
A.
3
B.
8
C.
9
D.
10
【简答题】已知等差数列{a n }为递增数列,满足 a 3 2 =5 a 1 +5 a 5 -25 ,在等比数列{b n }中,b 3 =a 2 +2,b 4 =a 3 +5,b 5 =a 4 +13. (Ⅰ)求数列{b n }的通项公式b n ; (Ⅱ)若数列{b n }的前n项和为S n ,求证:数列{ S n + 5 4 }是等比数列.
【简答题】若3,4,a和5,b,13是两组勾股数,则a+b的值是___________.
【单选题】以下程序运行的结果为( ) int &put(int n); int vals[10]; int error=-1; int main() { put(0)=12; put(9)=21; cout=0 && n<=9 ) { return vals[n]; } else { cout< return error; } }
A.
0000
B.
1221
C.
1209
D.
2109
【单选题】I have a friend who the piano very well.
A.
play
B.
playing
C.
plays
D.
played
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