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【简答题】
在等腰梯形ABCD中，AD∥BC，BC=4AD， ，∠B=45°．直角三角板含45°角的顶点E在边BC上移动，一直角边始终经过点A，斜边与CD交于点F，若△ABE是以AB为腰的等腰三角形，则CF的等于( )．
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η
B.
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C.
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D.
ηmin
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ηmin
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η>η max
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η min ≤η≤η max
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