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在等差数列{a n }中，a 1 =1，a 5 =9，在数列{b n }中，b 1 =2，且b n =2b n-1 -1，（n≥2） （1）求数列{a n }和{b n }的通项公式； （2）设 T n = a 1 b 1 -1 + a 2 b 2 - 1 + a 3 b 3 -1 +…+ a n b n -1 ，求T n ．
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