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根据对话内容，从对话后的选项中选出能填入空白处的最佳选项。选项中有两多余选项。 小题1: . I’d like four tickets to New York . Certainly . 小题2: On the 23rd next month . 23rd February ? Let me see . 小题3: What about 22nd ? The 22nd of February ? 小题4: It’s CA348 ? CA348 . When does it leave ? 13:15 hours . 小题5: That’s right . Thank you very much . Sorry , I’m not free at 13:15 . Yes , that ‘ll do . What’s the flight number ? Um , I’m afraid we don’t have any planes on that date to New York . What can I do for you , sir ? When would you like to fly there , please ? 13:15 hours- er , that’s a quarter past one in the afternoon , isn’t it ? Sorry , we don’t have any flights to New York that day . What about Washington D.C.
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【简答题】小红和小丽对问题“若方程组 a 1 x+ b 1 y= c 1 a 2 x+ b 2 y= c 2 的解是 x=3 y=-4 ，求方程组 3 a 1 x+2 b 1 y=5 c 1 3 a 2 x+2 b x y=5 c 2 的解”提出各自的想法．小红说：“这个题目好象条件不够，不能求解”；小丽说：“能不能把第二个方程组的两个方程的两边都除以5，通过整体代换的方法来解决”．参考他们的讨论，你认为这...
【简答题】I have a friend who lives by a three-word philosophy: Seize the moment. Just possibly, she may be the wisest woman on this planet. Too many people put off something that brings them joy just because t...
【单选题】根据下列文章,请回答 16～20 题。 I have a friend who is a team leader of about 25 employees who are primarily women. She' s found a trick that works for her most of the time, but not always. Those staff who appear...
A.
We shall not be moved.
B.
Money means .
C.
Photos taking are pleasant.
D.
There are people who are so careless about dressing.
E.
Action speaks louder than words.
F.
It is our society that must be blamed.
G.
You should wear appropriately where you are.
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A.
为教师的演示教学提供新的方式
B.
扩大和紧密英语学习的共同体
C.
促进学生主动构建的英语学习
D.
创设英语学习环境
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【单选题】下述程序的输出结果是( )。 #include ＜stdio.h＞ int f(n) int n { if(n==0 | | n==1) return 3 return n-f(n-2) } void main() {printf('/n%d',f(10)) }
A.
3
B.
8
C.
9
D.
10
【简答题】已知等差数列{a n }为递增数列，满足 a 3 2 =5 a 1 +5 a 5 -25 ，在等比数列{b n }中，b 3 =a 2 +2，b 4 =a 3 +5，b 5 =a 4 +13． （Ⅰ）求数列{b n }的通项公式b n ； （Ⅱ）若数列{b n }的前n项和为S n ，求证：数列{ S n + 5 4 }是等比数列．
【简答题】若3,4,a和5,b,13是两组勾股数,则a+b的值是___________.
【单选题】以下程序运行的结果为( ) int &put(int n); int vals[10]; int error=-1; int main() { put(0)=12; put(9)=21; cout=0 && n<=9 ) { return vals[n]; } else { cout< return error; } }
A.
0000
B.
1221
C.
1209
D.
2109
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