【简答题】Base on the following operator precedence grammar G[S]: S→a|^|(T) T→T,S|S Calculate the operator higher precedence than (.>), the operator lower precedence than (<.) and the operator same precedence o...
【判断题】Using other relations To Construct Operator Precedence Relations: 1 a ≒ b Û P→...ab... or P→..aQb... 2 = ((LAST*)(LASTTERM)) T (±) = (LASTTERM+) T (±)
【判断题】An operator grammar is one in which there are no productions containing consecutive non-terminal symbols. In such a grammar, no sentential form contains consecutive non-terminals (simple to prove this...
【判断题】Using definitions To Construct Operator Precedence Relations: 1 a ≒ b Û P→...ab... or P→..aQb... 2 Definition Û FIRSTVT(P)={a|P ⇒+ a... or P ⇒+ Qa...} LASTVT(P)={a|P ⇒+ ... a or P ⇒+ ... aQ} If there ...