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(1)选修4-2:矩阵与变换 已知向量 1 -1 在矩阵 M= 1 m 0 1 变换下得到的向量是 0 -1 . (Ⅰ)求m的值; (Ⅱ)求曲线y 2 -x+y=0在矩阵M -1 对应的线性变换作用下得到的曲线方程. (2)选修4-4:极坐标与参数方程 在直角坐标平面内,以坐标原点O为极点,x轴的非负半轴为极轴建立极坐标系.已知点M的极坐标为 (4 2 , π 4 ) ,曲线C的参数方程为 x=1+ 2 cosα y= 2 sinα (α为参数). (Ⅰ)求直线OM的直角坐标方程; (Ⅱ)求点M到曲线C上的点的距离的最小值. (3)选修4-5:不等式选讲 设实数a,b满足2a+b=9. (Ⅰ)若|9-b|+|a|<3,求a的取值范围; (Ⅱ)若a,b>0,且z=a 2 b,求z的最大值.
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【简答题】A very young boy, Tom, lives a long way from the city. One day he goes to the city to visit his friend, Jack. Jack asks Tom to have lunch together. They go into the restaurant and sit down at a table....
【单选题】听力原文:M: I' m afraid that I don' t like your hat, really. I think it' s a bit old fashioned for you. It goes well with the shoes, though. W: Old fashioned? It's back in fashion now. It's you that's old...
A.
The man thinks the hat fit well with the shoes, and he likes it.
B.
Although the hat is old fashioned, the woman likes it very much.
C.
The woman thinks the hat is fashionable but the man is out of fashion.
D.
The man doesn' t like the hat because it was not nice with the shoes.
【多选题】水热 - 溶剂热与固相反应的主要区别是:
A.
水热 - 溶剂热适用液相反应机理;固相反应适用界面扩散机理。
B.
水热 - 溶剂热合成材料在液相条件下,能提供相对稳定、均匀的反应条件;固相反应受反应物颗粒细度的影响较大。
C.
水热 - 溶剂热合成材料能合成完美的晶体;一般容易生成非整数化学计量比化合物。
【单选题】垫层的宽度应与路基同宽,最小厚度为( )mm。
A.
150
B.
200
C.
250
D.
300
【简答题】阅读理解。 Jack is a twenty-year-old young man. Two years ago, when he finished middle school, he found work in a shop. Usually he works until ten o'clock at night. He is very tired when he gets home. Afte...
【单选题】垫层的宽度应与路基宽度相同,其最小厚度为( )mm。
A.
50
B.
150
C.
120
D.
100
【单选题】水泥混凝土垫层的宽度应与路基同宽,其最小厚度为( ) mm。
A.
100
B.
150
C.
200
D.
180
【简答题】阅读理解。根据短文,正确的写T,错误的写F。 Li Ping is a Young Pioneer (员). He goes to the wildlife park (野生动物园). When he waits for a bus at the bus stop, he finds a watch on the road (马路). He asks some people, 'Whose ...
【单选题】垫层的宽度应与路基宽度相同,其最小厚度为( )
A.
150mm
B.
160mm
C.
170mm
D.
180mm
【简答题】阅读理解 Li Ping is a Young Pioneer (员). He goes to the wildlife park (野生动物园). When he waits for a bus at the bus stop, he finds a watch on the road (马路). He asks some people, 'Whose watch is it?' But ...
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