以下程序的输出结果是 #include struct st { int xint *y}*p int dt[4]={10,20,30,40} struct st aa[4]={50,&dt[0],60,&dt[0],60,&dt[0],60,&dt[0],} main() { p=aa printf('%d/n',++(p->x))}
A.
10
B.
11
C.
51
D.
60
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举一反三
【简答题】A. The “Win-win” solution. B. The “Lose-lose” solution. C. Learning to win arguments at home. D. Learning to take control at home.