In the illustrated circuit, us=50sin V, the active power (the average power)on a 5 Ω resistor is P1=I1.^2*R1=10 W, the active power of the resistor R2=10Ω is calculated by the equation P2=I2.^2*R2=20W. We can find out that I1=I2=sqrt(2)=1.414A,the total active power of this circuit is equal to P1+P2,that is 30W.The effective value of the voltage us is equal to 25*sqrt(2) V. Then the power factor cos φ =Ptotal/(Us*I) of the entire circuit is _________.Choose A,B,C or D.