已知1 mol CH 4 气体完全燃烧生成气态CO 2 和液态H 2 O,放出890.3 kJ热量,则表示该反应的热化学方程式正确的是 ( )
A.
CH 4 (g)+2O 2 (g) = CO 2 (g)+2H 2 O(g) ΔH=+890.3 kJ·mol -1
B.
CH 4 (g)+2O 2 (g) = CO 2 (g)+2H 2 O(l) ΔH=-890.3 kJ·mol -1
C.
CH 4 (g)+2O 2 (g) = CO 2 (g)+2H 2 O(l) ΔH=+890.3 kJ·mol -1
D.
CH 4 (g)+2O 2 (g) = CO 2 (g)+2H 2 O(g) ΔH=-890.3 kJ·mol -