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【简答题】
A．The amount of skin affected by the cut. B．The cause of the cut. C．The amount of bleeding. D．The number of nerve endings irritated.
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举一反三
【单选题】已知： C(s)+1／2 O 2 (g_)=CO(g)；△H 1 =' -110.35' kJ／mol CO(g)+1／2 O 2 (g)=CO 2 (g)；△H 2 =' -282.57' kJ／mol 则：C(s)+O 2 (g)=CO 2 (g)；△H 3 =
A.
+172.22 kJ／mol
B.
-172.22 kJ／mol
C.
+392.92 kJ／mol
D.
-392.92 kJ／mol
【简答题】The ______ line directs you to the specific book.
【单选题】 class Line { 11. public static class Point { } 12. } 13. 14. class Triangle { 15. // insert code here 16. } Which code， inserted at line 15， creates an instance of the Point class defined in L...
A.
Point p = new Point（）；
B.
Line.Point p = new Line.Point（）；
C.
The Point class cannot be instatiated at line 15.
D.
Line 1 = new Line（） ； 1.Point p = new 1.Point（）；
【单选题】已知：① C (s) + O 2 (g) CO (g) △H =' –' 110.5 kJ · mol – 1 ② C (s) + O 2 (g) CO 2 (g) △H =' –' 393.51 kJ · mol – 1 则反应：C (s) + CO 2 (g) 2CO (g) 的△H为（ ）
A.
– 283.01 kJ · mol – 1
B.
+ 172.51 kJ · mol –1
C.
+ 283.01 kJ · mol – 1
D.
+ 504.00 kJ · mol – 1
【简答题】已知： C(s)＋O 2 (g)＝CO 2 (g) ΔH＝－393．5 kJ/mol 2CO(g)＋O 2 (g)＝2CO 2 (g) ΔH＝－566 kJ/mol TiO 2 (s)＋2Cl 2 (g)＝TiCl 4 (s)＋O 2 (g) ΔH＝+141 kJ/mol 则TiO 2 (s)＋2Cl 2 (g)＋2C(s)＝TiCl 4 (s)＋2CO(g) ΔH＝ 。
【单选题】___ is measured from the baseline to the summer load line at the midship section.
A.
Extreme draft
B.
Molded draft
C.
Extreme depth
D.
Molded depth
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