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【判断题】
陶艺作品创作的流程一般分创意构思、创作草图、作品制作、作品施釉与烧成几个步骤。
A.
正确
B.
错误
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参考答案:
举一反三
【单选题】What impact would it bring if the current situationis not controlled?
A.
There would be a big explosion.
B.
There would be climate change.
C.
There would be an ecological damage.
D.
There would be natural disaster.
【简答题】本程序的功能:查找所有满足下面条件的两个整数对:1、两个整数都是3位数;2、组成两个整数各位的数字各不相同并且不出现数字0;3、第二个数等于第一个数的两倍。 例如,134和268就是满足该条件的一个整数对。 #include int main() { int a,b,c,j,k,w,e[6],sum; for(a=1; a999) 1 、 ; e[3]=sum/100; e[4]=(sum-e...
【单选题】在窗体上画一个名称为Command1的命令按钮,然后编写如下程序: Option Base 1 Private Sub Command1_Click() Dim a As Variant a = Array(1, 2, 3, 4, 5) Sum = 0 For i = 1 To 5 Sum = Sum + a(i) Next i x = Sum / 5 For i = 1 To 5 If a(i)...
A.
1 2 3
B.
3 4 5
C.
4 5
D.
1 2
【单选题】在窗体上画一个名称为 Command1 的命令按钮,然后编写如下程序: Option Base 1 Private Sub Command1_Click() Dim a As Variant a = Array(1, 2, 3, 4, 5) Sum = 0 For i = 1 To 5 Sum = Sum + a(i) Next i x = Sum / 5 For i = 1 To 5 If a(...
A.
1
B.
123
C.
345
D.
45
【单选题】#include void main() { int a[10]={0,1,2,3,4,5,6,7,8,9}, b[10],i,sum=0; for(i=1;i<10;i++) { b[i]=a[i-1]+a[i]; sum=sum+b[i]; } for(i=1;i<10;i++) if(i%3==0) sum=sum+b[i]; printf("sum=%3d",...
A.
sum=112
B.
sum=113
C.
sum=114
D.
sum=115
【单选题】What would happen if the reader were dissatisfied with the newspaper?
A.
The newspaper would send a complimentary issue.
B.
The subscription would be extended.
C.
The reader would be contacted.
D.
The subscription price would be refunded.
【简答题】在窗体上画一个名称为Command1的命令按钮,然后编写如下程序: Option Base 1 Private Sub Command1_Click() Dim a As Variant a = Array(1, 2, 3, 4, 5) Sum = 0 For i = 1 To 5 Sum = Sum + a(i) Next i x...
【单选题】A:( ), David? B:An orange juice.
A.
What do you like
B.
What would you like
C.
Would you like an orange juice
【单选题】What is sum after the following loop terminates? sum = 0 item = 0 while item 4: break print(sum)
A.
8
B.
7
C.
6
D.
5
【单选题】以下程序的运行结果是() #include int fun(int *a,int *b,int n) { int i=0,j=0,sum=0; for(;i { sum+=a[i]; if((i+1)%2==0) { b[j++]=sum; sum=0; } } return j; } int main() { int a[8]={1,0,2,3,5,4,2,1},b[8],k,i; k=fun(...
A.
0 2 4 2
B.
1 5 9 3
C.
1 3 5 1
D.
2 8 6
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