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【简答题】
读短文，回答问题。 Peter went to the library yesterday. He got up early and went to the library after breakfast. Usually Peter goes to the library by bus and that day he had a new idea. He went on his new bike. In the library he saw some new science books and he really wanted to read them all but he couldn't. He could only have three books at a time. He took the books and walked out of the library. He went to his bike but he couldn't open it with his key. What was wrong? He looked at the key and then looked at the bike. Oh, no. It wasn't his. His bike was next to it on the right! 1. How does Peter usually go to the library? ______________________________________________________ 2. How did Peter go to the library that day? ______________________________________________________ 3. What did Peter see in the library? ______________________________________________________ 4. Why he couldn't open the bike? ______________________________________________________
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【多选题】速卖通平台产品搜索排名是综合考虑多方面因素,目前搜索排名的参考维度主要是()
A.
商品的信息描述质量
B.
商品与买家搜索需求的相关性
C.
商品的交易转化能力
D.
卖家的服务能力
【单选题】下面一段代码中break语句起到( )的作用。 int pointer = 1; while (pointer <= 100) { switch(pointer % 3) { case 1: pointer +=1; break; case 2: pointer +=2; break; case 3: pointer +=3; break; } pointer++; }
A.
结束当次循环，使控制权直接转移到控制循环的条件表达式
B.
从嵌套循环内部跳出最里面的循环
C.
终止switch语句的语句序列
D.
退出循环
【单选题】帮助术后带有引流管的病人翻身侧卧时,下列方法正确的是
A.
翻身前夹闭引流管
B.
两人翻身时着力点分别位于肩、腰、臀、膝部
C.
翻身后再更换伤口散料
D.
翻身后将病人上面腿稍伸直,下面腿弯曲
E.
在病人两膝之间夹上软枕
【单选题】The ______ controls a pointer On the screen ．When you move it，?the pointer moves too．
A.
menu
B.
icon
C.
mouse
D.
click
【简答题】端口扫描的防范也称为 ,主要有 和 。
【单选题】帮助术后带有引流管的病人翻身侧卧时下列正确的是
A.
翻身前夹闭引流管
B.
翻身后再换伤口敷料
C.
在病人两膝间加上软垫
D.
两人翻身时着力点分别位于肩、腰、臀、膝部
E.
翻身后将病人上腿伸直,下腿弯曲
【单选题】帮助术后带有引流管的病人翻身侧卧时,下列方法正确的是
A.
翻身前夹闭引流管
B.
两人翻身时着力点分别位于肩、腰臀膝部
C.
翻身后再更换伤口敷料
D.
翻身后将病人上面腿稍伸直，下面腿弯曲
E.
在病人两膝之间夹上软枕
【多选题】速卖通平台搜索排名是综合考虑多方面因素,目前的搜索排名的参考维度主要考虑()
A.
商品的信息描述质量
B.
商品与买家搜索需求的相关性
C.
商品的交易转化能力
D.
卖家的服务能力
E.
搜索作弊的情况
【简答题】设” int a[10];*pointer=a; ”以下不正确的表达式是 ( ) 。A. pointer=a+5; B. a=pointer+a; C. a[2]=pointer[4]; D. *pointer=a[0];
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