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【简答题】
使用数字式万用电表如何测量交流电压?
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举一反三
【单选题】News report -1
A.
The UK is a good film location
B.
The cast usually comes from Britain
C.
Hollywood emphasizes quality
D.
Production cost can be reduced
【单选题】News report 1: W hat is news report mainly about?
A.
The return of a bottled message to its owner's daughter.
B.
A New Hampshire man's joke with friends on his wife.
C.
A father's message for his daughter.
D.
The history of a century-old motel.
【单选题】查看当前用户所拥有的对象权限使用的数据字典视图是
A.
system_privilege_map
B.
table_privilege_map
C.
user_sys_privs
D.
user_tab_privs
【单选题】News Report 1
A.
More than $1,400 a year.
B.
More than $4,000 a year.
C.
More than $14,000 a year.
D.
More than $40,000 a year.
【简答题】News report 1
【简答题】《春秋》的作者是
【简答题】如图，矩形ABCD中，BC=2，AB=1，PA丄平面ABCD，BE ∥ PA，BE= 1 2 PA ，F为PA的中点． （I）求证：DF ∥ 平面PEC （II）若PE= 2 ，求平面PEC与平面PAD所成锐二面角的余弦值．
【单选题】以下是输出杨辉三角的代码,请对横线处的代码进行补充完善。 #include using namespace std; const int N = 10; void getYHTriangle(int(*)[N]); void print(int(*)[N]); int main() { int a[N][N] = {}; getYHTriangle(a); print(a); return 0;...
A.
pa[i-1][j-1] = pa[i - 1][j] + pa[i - 1][j - 1]
B.
pa[i][j] = pa[i - 1][j] + pa[i - 1][j - 1]
C.
pa[i+1][j+1] = pa[i][j] + pa[i][j]
D.
pa[i][j] = pa[i][j-1] + pa[i - 1][j - 1]
【简答题】void main( ) { int a[10],b'10],*pa,*pb; pa=a; pb=b; for(int i=0;i<3;i++,pa++,pb++) { *pa=i; *pb=2*i; } pa=&a[0]; pb=&b[0]; for(int i=0;i<3;i++) { *pa=*pa+i; *pb=*pb+i; cout<<*pa++<<","<<*pb++<<","; }...
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