计算:(1)若数列 a n = 1 n(n-1) ,求 lim n→∞ ( a 2 + a 3 + a 4 +…+ a n ) ; (2)若函数 f(x)= x -1 x?(x-1) (x>1) a+ 2 x (x≤1) 在R上是连续函数,求a的取值.
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